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Mathe - Termumformung

Intermediate

Tuesday, May 16th 2006, 3:10pm

Mathe - Termumformung

Hallo Leute,

und war gehts um folgendes:
Ich soll den oberen Radius von einem Kegelstumpf berechnen.

Die Formel lautet: V=((pi+h)/3)*((r1)^2+r1)*(r2+(r2)^2)

V=17306cm^3
r1=8cm
h=25cm
r2=

Ich komm irgendwie nicht mit der Terumformung kla, kann mir jemand mal Starthilfe geben?
Dankeschön

sc0pe

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Sage

Occupation: GER

Tuesday, May 16th 2006, 3:16pm

r=r1, r=r2

(3V)/(Pi*h*(r²+r)) = r²+r

r²+r - (3V)/(Pi*h*(r²+r)) = 0

(3V)/(Pi*h*(r²+r)) kannst du ausrechnen und dann einfach p-q-Formel benutzen X_X

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Intermediate

Tuesday, May 16th 2006, 9:18pm

thx

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Professional

Occupation: GER

Tuesday, May 16th 2006, 10:39pm

wie geht nomma p-q formel??

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Intermediate

Location: Nähe Dresden

Tuesday, May 16th 2006, 10:51pm

x1/2= -p/2+-(p²/2-q)^1/2

This post has been edited 1 times, last edit by "DarkRevenger" (May 16th 2006, 10:51pm)

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Sage

Location: Hildesheim

Occupation: GER

Tuesday, May 16th 2006, 11:09pm

Quoted

Original von DarkRevenger
x1/2= -p/2+-(p²/2-q)^1/2

eher
x1/2= -p/2+-((p/2)²-q)^1/2

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Intermediate

Location: Nähe Dresden

Tuesday, May 16th 2006, 11:12pm

Ja, ich hab da die 4 vertan

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